Moderators: Chem_Mod, Chem_Admin

Jade Fosburgh Discussion 2C
Posts: 59
Joined: Fri Sep 29, 2017 7:07 am


Postby Jade Fosburgh Discussion 2C » Tue Jan 30, 2018 12:34 pm

This homework problem says to

calculate the change in entropy when the pressure of 1.50 mol Ne(g) is decreased isothermally from 15.0 atm to 0.500 atm. Assume ideal behavior.

I believe we uses the equation

delta S = n*R*ln(P2/P1)

But what R value do we use? The 8.314 J/K*mol value wouldnt cancel with the atm right?

Posts: 5
Joined: Fri Jun 17, 2016 11:28 am

Re: 9.11

Postby 904676178 » Tue Jan 30, 2018 12:56 pm

I believe yes we do use that r value (8.314J/K*MOL) and the atm should just cancel each other out when you divide (p2/p1). so you are left with JK-1 in answer.

Sarah Sharma 2J
Posts: 33
Joined: Fri Sep 29, 2017 7:05 am

Re: 9.11

Postby Sarah Sharma 2J » Tue Jan 30, 2018 1:28 pm

Since you are working with ideal gases you would use the R value of 8.314 J/K mol.

Return to “Entropy Changes Due to Changes in Volume and Temperature”

Who is online

Users browsing this forum: No registered users and 1 guest