## 9. 43

Volume: $\Delta S = nR\ln \frac{V_{2}}{V_{1}}$
Temperature: $\Delta S = nC\ln \frac{T_{2}}{T_{1}}$

Payton Schwesinger 1J
Posts: 45
Joined: Fri Sep 29, 2017 7:04 am

### 9. 43

In problem 9.43, when calculating the entropy changes for the different volume and temperature changes, they used the number 75.3 KJ/ K mol as the specific molar heat capacity. How did they calculate this value?

Tanaisha Italia 1B
Posts: 55
Joined: Fri Sep 29, 2017 7:04 am

### Re: 9. 43

I don't think that you will have to calculate the value, it will usually be given to you (either by a table in the textbook or in the problem itself).

Posts: 88
Joined: Fri Sep 29, 2017 7:03 am

### Re: 9. 43

Yes, I think the heat capacity will usually be given to you.

Amy Zheng 2l
Posts: 57
Joined: Fri Sep 29, 2017 7:04 am

### Re: 9. 43

its on the formula sheet!

Jennie Fox 1D
Posts: 66
Joined: Sat Jul 22, 2017 3:01 am

### Re: 9. 43

You won't have to calculate it, it should be given in the problem. They make you look it up in the book for the homework problems, but on the test it will be given.

204932558
Posts: 23
Joined: Fri Sep 29, 2017 7:05 am

### Re: 9. 43

The value is fixed and given, so you don't have to calculate it.