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Hannah Guo 3D
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Postby Hannah Guo 3D » Wed Feb 07, 2018 8:54 pm

9.47 Initially a sample of ideal gas at 323 K occupies 1.67 L at 4.95 atm. The gas is allowed to expand to 7.33 L by two pathways: (a) isothermal, reversible expansion; (b) isothermal, irreversible free expansion. Calculate Stot, S, and Ssurr for each pathway.

For (a), why since the process is reversible, delta Stot=0?
Thank you!

Christy Lee 2H
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Re: 9.47

Postby Christy Lee 2H » Wed Feb 07, 2018 9:25 pm

For a reversible process, the reaction is assumed to be at equilibrium which means deltaS of the universe is zero because there is no entropy change at equilibrium.

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