## Irreversible expansion and entropy [ENDORSED]

Volume: $\Delta S = nR\ln \frac{V_{2}}{V_{1}}$
Temperature: $\Delta S = nC\ln \frac{T_{2}}{T_{1}}$

Helen Shi 1J
Posts: 78
Joined: Sat Jul 22, 2017 3:00 am

### Irreversible expansion and entropy

Why is it that in a free expansion (according to page 346 in the textbook) that delta S of the surroundings is equal to 0 but delta S (system) is not. The book reasons that no work is done in free expansion so q=0, but if that is the case how can delta S (system) or delta S (total) be anything other than zero?

Rachel Formaker 1E
Posts: 86
Joined: Fri Sep 29, 2017 7:04 am
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### Re: Irreversible expansion and entropy  [ENDORSED]

ΔS of the system will increase because in free expansion, the volume of the system will still increase, so the particles can occupy more microstates, representing an increase in entropy.

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