9.47 Isothermal Irreversible Free Expansion

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Cam Bear 2F
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Joined: Thu Jul 27, 2017 3:01 am

9.47 Isothermal Irreversible Free Expansion

Postby Cam Bear 2F » Wed Feb 14, 2018 11:42 am

When solving part b asking about the isothermal irreversible free expansion of an ideal gas, if the expansion is irreversible and w=0, how do we calculate the entropy change of the system? The solutions manual says it is equal to 3.84J/K (the entropy change in the isothermal reversible expansion). Can anyone explain why? Thanks!

Clara Hu 1G
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Re: 9.47 Isothermal Irreversible Free Expansion

Postby Clara Hu 1G » Wed Feb 14, 2018 1:41 pm

You would use

Tatiana Hage 2E
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Re: 9.47 Isothermal Irreversible Free Expansion

Postby Tatiana Hage 2E » Wed Feb 14, 2018 2:47 pm

It would be the same as ΔSsys of part a, the isothermal and reversible process. ΔSsurr = 0 for free expansion so ΔStot = ΔSsys.

Janine Chan 2K
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Re: 9.47 Isothermal Irreversible Free Expansion

Postby Janine Chan 2K » Wed Feb 14, 2018 9:12 pm

Since entropy is a state function, the pathway taken from final to initial doesn't matter. ∆Ssys for irreversible and reversible should be the same.


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