Midterm Question 6B

Volume:
Temperature:

Moderators: Chem_Mod, Chem_Admin

Katelyn 2E
Posts: 35
Joined: Sat Jul 22, 2017 3:01 am

Midterm Question 6B

Postby Katelyn 2E » Tue Mar 13, 2018 11:47 pm

Can anyone explain/provide their work for this question? For further reference, it is the one where 2/3 of the question was taken out and the one that remained was "under constant volume." How would you figure out moles for this question, too?

Kelly Kiremidjian 1C
Posts: 62
Joined: Fri Sep 29, 2017 7:04 am

Re: Midterm Question 6B

Postby Kelly Kiremidjian 1C » Wed Mar 14, 2018 12:15 am

For this question I used the equation deltaS=nCvln(T2/T1)

You need to find the moles first, however using PV=nRT. Everything is given besides moles, so you can solve for n:
n=(1.00 atm)(53.48L)/(.08206)(303K) to get n=2.15 moles.

You can then use n to solve for change in entropy, using Cv as 3/2R because its constant volune:
deltaS=(2.15)(3/2)(8.314)ln (333K/303K)
and you should get deltaS=2.53 J x K-1

Hope this helps!


Return to “Entropy Changes Due to Changes in Volume and Temperature”

Who is online

Users browsing this forum: No registered users and 2 guests