## clarification

Volume: $\Delta S = nR\ln \frac{V_{2}}{V_{1}}$
Temperature: $\Delta S = nC\ln \frac{T_{2}}{T_{1}}$

katherinemurk 2B
Posts: 68
Joined: Wed Nov 15, 2017 3:02 am

### clarification

To clarify, when the reaction is reversible delta S is 0?

Elaine Pham 2E
Posts: 58
Joined: Fri Sep 28, 2018 12:28 am
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### Re: clarification

Yes I think so because reversible means the process is at equilibrium so there is no change in entropy.