Changes in Pressure


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Changes in Pressure

Postby 605168557 » Wed Feb 13, 2019 11:32 pm

Why is the ratio (P1/P2) in the equation deltaS=nRln(P1/P2) instead of (P2/P1) like with the case of changing volume and changing temperature?

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Re: Changes in Pressure

Postby Felicia1E » Wed Feb 13, 2019 11:52 pm

It has to do with the equation PV=nRT. P and V are inversely related, so in the formula, you would also have to make sure your terms are inverses. It should be that if you have P1 corresponding to V1 and a P2 corresponding to a V2, which you can find one by the other through PV=nRT, deltaS=nRln(P1/P2) will yield you the same answer as deltaS=nRln(T2/T1).

Sarah Kiamanesh 1D
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Re: Changes in Pressure

Postby Sarah Kiamanesh 1D » Thu Feb 14, 2019 10:16 am

as given by Boyle's law, P1V1=P2V2. If you divide the P2 over to the left and the V1 over to the right, the relation becomes
P1/P2 = V2/V1. The left side of the equation is therefore interchangeable with the ratio on the right

Riley Dean 2D
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Re: Changes in Pressure

Postby Riley Dean 2D » Sat Feb 16, 2019 5:05 pm

Because the equation P1V1=P2V2 is true, you can manipulate it so P1/P2=V2/V1

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Re: Changes in Pressure

Postby maldonadojs » Sat Feb 16, 2019 5:47 pm

This is tied back to the equation PV=nRT. Due to 'P' and 'V' being multiplied together, they are inversely proportional. When volume goes up, pressure goes down and vice versa.

Ashe Chen 2C
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Re: Changes in Pressure

Postby Ashe Chen 2C » Sat Feb 16, 2019 9:44 pm

because of the ideal gas law, pressure and volume have an inverse relationship and thus when volume increases, pressure decreases.

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