## Irreversible Process

Volume: $\Delta S = nR\ln \frac{V_{2}}{V_{1}}$
Temperature: $\Delta S = nC\ln \frac{T_{2}}{T_{1}}$

Moderators: Chem_Mod, Chem_Admin

JChen_2I
Posts: 107
Joined: Fri Aug 09, 2019 12:17 am

### Irreversible Process

does an isothermal, irreversible free expansion mean there's no change in entropy of the surroundings?

alex_4l
Posts: 109
Joined: Thu Sep 26, 2019 12:18 am

### Re: Irreversible Process

Isothermal is when the temperature is constant even though heat and volume change very slowly so other properties can adjust (making it seem like temperature is constant). When heat is added, volume expands and the pressure changes. Isothermal shows that Delta U = Q - W = 0 because the internal energy does not change
With that being said, the work equation has to then take the integral of the change in pressure and the differential volume
Hope that helps!

Return to “Entropy Changes Due to Changes in Volume and Temperature”

### Who is online

Users browsing this forum: No registered users and 3 guests