Problem 4I.5


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Savannah Mance 4G
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Joined: Fri Aug 30, 2019 12:17 am

Problem 4I.5

Postby Savannah Mance 4G » Thu Feb 27, 2020 12:35 pm

When finding the equilibrium temperature of water I don't understand why you wouldn't multiply the grams given by the specific heat capacity for the how water and the cold water? Why do they just cancel?

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Re: Problem 4I.5

Postby DarrenKim_1H » Thu Feb 27, 2020 2:25 pm

I think it's because since q = mCdeltaT and you set qhot equal to qcold, you can divide both sides by the specific heat capacity of water to cancel them out, since you're finding the equilibrium temperature.

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Re: Problem 4I.5

Postby Uisa_Manumaleuna_3E » Fri Feb 28, 2020 4:11 pm

the way I understand it, both the cold water and the hot water have the exact same specific heat capacity, so when we set them to one another (q of cold = - q of hot) it just makes it simpler knowing that we can divide both sides without having to do any extra calculations

I imagine that if you do end up multiplying both sides by the specific heat capacity (being sure that the units match up properly) you will still get the same answer. But for me I always run the risk of messing up with extra unnecessary calculations

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