ΔS total= 0

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Sunny Wu 3A
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ΔS total= 0

Postby Sunny Wu 3A » Wed Feb 17, 2021 4:22 pm

In what scenario does -ΔSsurr=ΔSsystem?

shevanti_kumar_1E
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Re: ΔS total= 0

Postby shevanti_kumar_1E » Wed Feb 17, 2021 4:35 pm

You can use that when Delta S of the universe equals 0 because
Delta S(universe)=delta S(sys)+Delta S(surr)

Delta S(universe)=0 when the reaction is at reversible reaction is at 0.This is because the heat that flows into the surroundings is being released by the system.

edward_brodell_2I
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Re: ΔS total= 0

Postby edward_brodell_2I » Mon Feb 22, 2021 7:56 pm

Also, if the thermal universe is considered isolated than any changes inside are contained and exact transactions. Whatever entropy is lost or gained by the system will be lost/gained by the surroundings.

Kyla Roche 2K
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Re: ΔS total= 0

Postby Kyla Roche 2K » Tue Feb 23, 2021 8:34 am

For a reversible reaction, delta S (surrounding) + delta S (system) = 0 so S (system) = -delta S (surrounding)

Kimiya Aframian IB
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Re: ΔS total= 0

Postby Kimiya Aframian IB » Tue Feb 23, 2021 9:00 am

Sunny Wu 3A wrote:In what scenario does -ΔSsurr=ΔSsystem?

Hi! The scenario in which that statement is true is when delta S universe=0, which is for a reversible reaction because it is slow enough for the surroundings to restore the heat lost by work, therefore making the change in the universe 0. Hope this helps!

305572629
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Re: ΔS total= 0

Postby 305572629 » Tue Feb 23, 2021 12:22 pm

this scenario occurs in a reversible reaction! Since reversible reactions in real life occur slowly, the system has time to regain the heat lost by work, so the overall change in entropy of the universe is = to 0.

Chudi Onyedika 3A
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Re: ΔS total= 0

Postby Chudi Onyedika 3A » Sun Feb 28, 2021 3:54 pm

This occurs when the reaction is reversible.

Joshua Eidam 2A
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Re: ΔS total= 0

Postby Joshua Eidam 2A » Wed Mar 03, 2021 9:06 pm

When the reaction is reversible, then the ΔSuniverse= 0

Alexis Sanft 1E
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Re: ΔS total= 0

Postby Alexis Sanft 1E » Wed Mar 03, 2021 9:34 pm

Kimiya Aframian IB wrote:
Sunny Wu 3A wrote:In what scenario does -ΔSsurr=ΔSsystem?

Hi! The scenario in which that statement is true is when delta S universe=0, which is for a reversible reaction because it is slow enough for the surroundings to restore the heat lost by work, therefore making the change in the universe 0. Hope this helps!

Does this mean the system is at equilibrium?

Kiyoka Kim 3C
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Re: ΔS total= 0

Postby Kiyoka Kim 3C » Thu Mar 04, 2021 12:18 pm

Delta S total equals zero for a reversible process because essentially the change in temperature and pressure is very small, therefore the system is at thermodynamic equilibrium.

LarisaAssadourian2K
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Re: ΔS total= 0

Postby LarisaAssadourian2K » Thu Mar 04, 2021 12:29 pm

Hello! That applies to when the reaction is reversible.

Olivia Smith 2E
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Re: ΔS total= 0

Postby Olivia Smith 2E » Thu Mar 04, 2021 12:34 pm

It will happen in reversible reactions where delta s of the universe is equal to zero!

DPatel_2L
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Re: ΔS total= 0

Postby DPatel_2L » Sat Mar 06, 2021 6:32 pm

When the reaction is reversable.

Neha Jonnalagadda 2D
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Re: ΔS total= 0

Postby Neha Jonnalagadda 2D » Wed Jan 19, 2022 7:29 pm

This is true when S delta of the universe = 0.


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