Example 9.10

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Lily Guo 1D
Posts: 64
Joined: Fri Sep 29, 2017 7:03 am

Example 9.10

Postby Lily Guo 1D » Tue Feb 06, 2018 2:52 pm

Example 9.10 says, "Calculate the change in entropy of the surroundings when mercury freezes at 49 C; use Hfus(Hg) 2.292 kJ mol 1 at 49 C." It then goes on to solve the problem and sets T as (-49 + 273) K = 224 K. Are you just supposed to assume that the initial temperature is 0 C aka 273 K? What is that assumption based on?

Grace Han 2K
Posts: 33
Joined: Tue Nov 15, 2016 3:00 am

Re: Example 9.10

Postby Grace Han 2K » Tue Feb 06, 2018 4:29 pm

Hi, Im not sure if I understood your question clearly but basically, the initial temperature is not 0 degrees C. The T must be converted into Kelvin and so you have to add 273K to the given Celsius to get Kelvin for the temperature.

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