Calculate the change in molar entropy of an ideal gas when it is compressed isothermally to 1/3 its initial volume.
Can someone just walk me through that step by step please?
Self test 8.3A
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Re: Self test 8.3A
dS = R*ln (V2/V1)
If it is compress to 1/3 its initial volume, then V2= (1/3) V1
Plug in V2 into the equation and the V1 will cancel, so you have ln (1/3)
R=8.314 J/K*mol
change in molar entropy = 8.314 * ln (1/3) = -9.13 J/mol*K
If it is compress to 1/3 its initial volume, then V2= (1/3) V1
Plug in V2 into the equation and the V1 will cancel, so you have ln (1/3)
R=8.314 J/K*mol
change in molar entropy = 8.314 * ln (1/3) = -9.13 J/mol*K
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