Comparing standard molar entropies

[Marni Kahn 1A]

Why do larger, more complex molecules possess larger standard entropies than simpler, smaller molecules in the same phase?

[Kassidy Ford 1I]

Larger molecules have more particles and therefore have a greater positional entropy value. For example an element with more particles (electrons, protons, and neutrons) (such as Pb vs C) will have a larger degeneracy number, where W=#microstates^(#particles). Then use the equation S=kb(lnW) to solve for entropy

[Emma Popescu 1L]

There are more possible arrangements of atoms for larger, more complex molecules, increasing the number of possible microstates. So the value of W will be larger, thus causing a larger value of S.

[Sam McNeill 1E]

You can also think about how larger elements have more electrons, and the possible states that those electrons could occupy contribute to the positional entropy, causing it to have a larger entropy than smaller elements with the less electrons.

[Robin Cadd 1D]

Why do larger, more complex molecules possess larger standard entropies than simpler, smaller molecules in the same phase?

You could also think of more complex molecules having greater disorder, as there are more particles that make up the molecules (protons, electrons, etc.)

[RichBollini4G]

Larger molecules have more particles and therefore have a greater positional entropy value. For example an element with more particles (electrons, protons, and neutrons) (such as Pb vs C) will have a larger degeneracy number, where W=#microstates^(#particles). Then use the equation S=kb(lnW) to solve for entropy

Thank you

[Renee Grange 1I]

More complex molecules have larger standard molar entropies because there are more possible configurations and therefore more disorder, and therefore more entropy than smaller, less complex molecules.