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text problem 4J.5

Posted: Mon Mar 02, 2020 1:49 pm
by JosephineF
it is asking to write the balanced formation reaction for NH3. The solution manual says 1/2N2 + 3/2H2 --> NH3. Is there a formula for how to arrive at these numbers or is it just guess and check? I'm confused as to how 2 Ns goes to only 1 N and how H2 gains another H

Re: text problem 4J.5

Posted: Mon Mar 02, 2020 2:11 pm
by Parker Smith
the (1/2) N2 revers to only using a half mole of N2 (literally only one nitrogen molecule) to make one mole of NH3, which makes sense. Same applies with using (3/2) of the diatomic hydrogen to make one mole of NH3 (since 2x3=6 and 6/3=3, which lines up with the 3 hydrogen molecules in one mole of NH3)

Re: text problem 4J.5

Posted: Wed Mar 11, 2020 8:23 pm
by Ryan Yee 1J
If you count up the total molecules in these equations, both sides have equal numbers of the required atoms. The 1/2(N2) means that there is only 1 nitrogen atom, and the 3/2(H2) means there are 3 hydrogen atoms, so they both come together to make 1(NH3)