The textbook problem 4H.11 asks you to find ∆S for reactions using the reactants' & products' standard molar entropies.
For the reaction:
∆S° for the reaction = -36.81 J/(K•mol)
We have to explain why the entropy is decreasing as the reaction proceeds.
The answer key says:
"It is not immediately obvious, but the four moles of solid products are more ordered than the four moles of solid reactants."
What does that mean?
Entropies of Solid Products vs. Solid Reactants?
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Re: Entropies of Solid Products vs. Solid Reactants?
If you draw out the lewis structure, you see that KClO3 has more resonance than KClO4 and KCl. This is because KCl only has one figuration, which means it's more ordered and has lower entropy. I also think the molecular structure plays in, since ClO4 is tetrahedral while ClO3 is trigonal pyramidal. More resonance=more possible microstates= higher entropy. Hope this helped
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Re: Entropies of Solid Products vs. Solid Reactants?
Isabel_Eslabon_2G wrote:The textbook problem 4H.11 asks you to find ∆S for reactions using the reactants' & products' standard molar entropies.
For the reaction:
∆S° for the reaction = -36.81 J/(K•mol)
We have to explain why the entropy is decreasing as the reaction proceeds.
The answer key says:
"It is not immediately obvious, but the four moles of solid products are more ordered than the four moles of solid reactants."
What does that mean?
Even though you end up with 2 different types of products, you still end up with 4 moles of solid on both sides. So, you need to find which has more entropy in their structure, which ends up being the products as described by someone else.
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