## Delta G of ionization

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

ursulavictorino1K
Posts: 55
Joined: Sun Feb 17, 2019 12:15 am

### Delta G of ionization

Is deltaG of ionization the same as regular deltaG?

Posts: 49
Joined: Thu Jul 25, 2019 12:16 am

### Re: Delta G of ionization

yes

Jessica Chen 2C
Posts: 103
Joined: Thu Jul 11, 2019 12:17 am

### Re: Delta G of ionization

Yes, it just specifies that it's the delta G of an ionization reaction.

Tahlia Mullins
Posts: 105
Joined: Thu Jul 25, 2019 12:15 am

### Re: Delta G of ionization

Yes it is, it’s just a way to make it clear what the change in gibbs free energy is due to.