Wk.5 #11






Moderators: Chem_Mod, Chem_Admin

Jaclyn Padilla
Posts: 19
Joined: Mon Jan 03, 2022 9:25 am

Wk.5 #11

Postby Jaclyn Padilla » Mon Mar 20, 2023 11:50 am

For a particular reaction, ΔH=−238.4 kJ and ΔS=−80.0 J/K.
Calculate ΔG for this reaction at 298 K.

For this question I first used the formula deltaG=deltaH-TdeltaS.
Since I am given delta H and delta S I plug those into the formula along with the temperature in kelvins. Next I divided -80.0J/K by 1000J since we need to have the same units when multiplying. So by multiplying everything I got -214.6jk as deltaG.

Vanessa Nicoll 3H
Posts: 34
Joined: Mon Jan 09, 2023 10:07 am

Re: Wk.5 #11

Postby Vanessa Nicoll 3H » Mon Mar 20, 2023 11:59 am

Was it marked wrong? Every step seems to be right, if anything it might be a calculation error? If anything, try (-80.0J/k * 1kj/1000J) for delta S.


Return to “Gibbs Free Energy Concepts and Calculations”

Who is online

Users browsing this forum: No registered users and 5 guests