Gibb's Free Energy at Equilibrium
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Gibb's Free Energy at Equilibrium
Could someone explain to me why Gibb's free energy is = 0 at equilibrium. I understand that for a reaction it will be the dG of products - dG of reactants but beyond that why would the Gibb's free energy be 0 at equilibrium, like conceptually? Thanks!
Re: Gibb's Free Energy at Equilibrium
hi! it's because at equilibirium, it's where you want to be. So it won't have the spontaneous drive to go anywhere. It will want to stay at equilibrium.
Last edited by harper_2I on Wed Feb 21, 2024 9:26 pm, edited 1 time in total.
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Re: Gibb's Free Energy at Equilibrium
At equilibrium, the system has reached a rate where the forward and reverse reactions are occurring at equal rates. A system also tends towards minimizing free energy available to do work, and when it is at equilibrium, this energy is at a minimum (which is zero).
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Re: Gibb's Free Energy at Equilibrium
at equilibrium the reaction is not proceeding spontaneously in any direction and is thermodynamically balanced
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Re: Gibb's Free Energy at Equilibrium
Gibbs free energy is 0 at equilibrium because there is no net change in molar enthalpy within the system. Similar to concentration at equilibrium, the backward and forward reactions are occurring at the same rate.
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