## Predicting Gibbs Free Energy Sign

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Victoria_Reimers_3L
Posts: 16
Joined: Fri Sep 25, 2015 3:00 am

### Predicting Gibbs Free Energy Sign

Are you able to predict the sign of the Gibbs free energy for a reaction given only the temperature, and if so, how would you do this?

304621080
Posts: 20
Joined: Fri Sep 25, 2015 3:00 am

### Re: Predicting Gibbs Free Energy Sign

No, because it is also dependent on the enthalpy of the reaction.

Cameron_Greenberg_3C
Posts: 60
Joined: Fri Sep 28, 2018 12:26 am

### Re: Predicting Gibbs Free Energy Sign

Gibbs Free Energy is dependent on temperature, entropy, and enthalpy. A high temperature can still be multiplied by a positive or negative value of change in entropy, so just knowing the temperature does not give the sign of the Gibbs Free Energy value.

Katie Sy 1L
Posts: 57
Joined: Fri Sep 28, 2018 12:18 am

### Re: Predicting Gibbs Free Energy Sign

you can't predict it based on just temperature. you would need enthalpy or entropy or both