## 2008 Midterm HQ1A

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Marisa Mekkittikul2E
Posts: 6
Joined: Fri Sep 25, 2015 3:00 am

### 2008 Midterm HQ1A

Coupled reactions are used in organisms to drive important biochemical processes. Individual chemical reactions may be added together to form a net reaction, and the overall reaction Gibbs free energy is the sum of the individual Gibbs free energies of reaction. For example, ATP is the primary molecule that stores and releases energy to drive vital nonspontaneous chemical reactions in our bodies. However, the generation of ATP from ADP is nonspontaneous and must itself be coupled to a spontaneous reaction. This process is called oxidative phosphorylation. What amount (in moles) of ATP could be formed if all the Gibbs free energy released in the oxidation of three moles of NADH were used to generate ATP?

Question: Why is the final answer divided by 30.5kJ?

Chem_Mod
Posts: 19135
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 818 times

### Re: 2008 Midterm HQ1A

Could you give more details about the problem. I'm unable to find that practice midterm in the course reader. Presumably you need a some sort of chemical equation for the process.

Katrina_Domingo_3G
Posts: 23
Joined: Wed Sep 21, 2016 2:59 pm

### Re: 2008 Midterm HQ1A

What is the logic behind dividing it by 30.5 kJ?
Attachments