Gibbs and Electrochem

[Ashwin Babu 1I]

How can we use Gibbs free energy to predict the voltage of an electrochemical cell, and how does it relate to electrical work?

[Ashely_Pavon_2E]

Gibbs free energy and voltage are related by the equation J/V = C, where C is coulombs. However we convert it using faraday, so we get DeltaG=-nFEcell.

[vkhauv2004]

Gibbs free energy relates to the voltage or Ecell in which the equation for delta G = -nFE. If we are given the values of delta G and mols for n, we can find the value of Ecell through Ecell = - delta G/nF. As for electrical work, J/V = C which is coulombs.

[Sana M 1E]

Using the formula delta G(standard) = -nFE (standard), where delta G represents the Gibbs free energy, the E represents cell potential, one can find the voltage from Gibbs free energy or vice versa. The n is the number of moles while the F is represents Faraday's constant, which is equal to 96485 Coulombs/mole.