## Spontaneous

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Dianna Grigorian 1C
Posts: 72
Joined: Wed Sep 21, 2016 2:55 pm

### Spontaneous

Why is any decrease in Gibbs free energy, or negative delta G, considered favorable?

Nerissa_Low_2F
Posts: 23
Joined: Fri Jul 15, 2016 3:00 am

### Re: Spontaneous

I believe it is because you're going from a higher energy to a lower energy, which is more favorable than the opposite direction.