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Postby Joslyn_Santana_2B » Mon Jan 30, 2017 10:48 pm

1. Why does solution's manual use positive RTlnQ instead of negative? How do you know which equations to use?

2. The solution states, "Because deltaG is positive, the reaction will be spontaneous to produce I_2. I thought positive deltaG meant non-spontaneous ?
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Re: 11.15

Postby Chem_Mod » Mon Jan 30, 2017 11:59 pm

1. Because we know that the equation is not at equilibrium, we will instead use this equation.

If we were solving for , then we would use the following formula.

2. You are right, a positive delta G should be non-spontaneous.

David Julfayan 1F
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Re: 11.15

Postby David Julfayan 1F » Wed Feb 01, 2017 12:51 am

The way I understood it was that ∆G is positive so the reaction is spontaneous, favoring the reactants (going to the left to I_2). Its not spontaneous going to the right.

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