## Relationship between ΔG⁰ AND K

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

aTirumalai-1I
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### Relationship between ΔG⁰ AND K

Hi,

Can someone explain the relationship between ΔG⁰ AND K? In other words, how do we know that we can relate the equilibrium constant directly to changes in enthalpy and entropy?

Sabrina Dunbar 1I
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### Re: Relationship between ΔG⁰ AND K

The Kb that we are using here is not the same Kb as in acids and bases calculations. Here, we are using Boltzmann's constant, k = 1.38 x 10–23 J·K-1, to stand for Kb in free energy and entropy calculations. Hopefully this answers your question.

Lindsay Kester 2L
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Joined: Thu Jul 27, 2017 3:00 am

### Re: Relationship between ΔG⁰ AND K

The K here is also a constant for all equations, and doesn't change with each reaction/molecule being used.

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