## Chapter 9 Problem 115

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Maria1E
Posts: 61
Joined: Sat Jul 22, 2017 3:01 am

### Chapter 9 Problem 115

6Co2 (g) +6H2O (l) --> C6H12O6 (aq) + 6O2 (g)
deltaH = +2802 kJ

State the effect the following changes will have on the equilibrium composition.
I am confused on part e:
e) Some of the C6H12O6 is removed

The solution manual states that this would result in the favoring of the formation of products. However, I was under the impression that changing the amount of any molecule that isn't a gas wouldn't change the equilibrium composition. Why does removing C6H12O6 still change the equilibrium composition even though it is aqueous?

Sean Monji 2B
Posts: 66
Joined: Fri Sep 29, 2017 7:06 am

### Re: Chapter 9 Problem 115

Pure solids and liquids aren't included in chemical equilibrium equations themselves, but an aqueous solid or liquid is, therefore removing an aqueous product will result in the reaction favoring the formation of products. I think you just got tripped up in that aqueous molecules are also included in the equilibrium equation.
Hope that helps