## Gibbs “Available” energy

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Kellina Tran 2I
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Joined: Sat Jul 22, 2017 3:00 am

### Gibbs “Available” energy

Under what conditions did Dr. Lavelle mention that the energy available to do work is considered Gibbs free energy?

Curtis Tam 1J
Posts: 105
Joined: Thu Jul 13, 2017 3:00 am

### Re: Gibbs “Available” energy

I believe when it's under constant pressure and temperature. This has something to do with how we derive Gibbs Free Energy to get deltaG=wmax. It's found on page 355.

Jasmin Tran 1J
Posts: 54
Joined: Thu Jul 27, 2017 3:00 am

### Re: Gibbs “Available” energy

According to the original definition, Gibbs defines “available energy” as “the greatest amount of mechanical work which can be obtained from a given quantity of a certain substance in a given initial state, without increasing its total volume or allowing heat to pass to or from external bodies, except such as at the close of the processes are left in their initial condition.” Essentially, this means that volume and temperature are both constant, and work is done within a system and its surroundings.