## Delta G°

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Kathleen Vidanes 1E
Posts: 62
Joined: Fri Sep 29, 2017 7:07 am

### Delta G°

How do we know when delta G°is equal to 0? What does this mean?

Caroline Cox 1H
Posts: 18
Joined: Fri Sep 29, 2017 7:03 am

### Re: Delta G°

When delta G is zero that means the system is at equilibrium.

Emma Li 2C
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Been upvoted: 1 time

### Re: Delta G°

I think another way to say it is when the equilibrium constant equals 1!

Julianna Thrasher 1B
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Joined: Thu Jul 27, 2017 3:00 am

### Re: Delta G°

When ΔG=0 then the system is at equilibrium, not when ΔG° is 0. G° is standard free energy of a gas at 1atm. If G°=0 I believe it means there is no free energy due to change in pressures.

Tia Tomescu 2D
Posts: 42
Joined: Fri Sep 29, 2017 7:06 am

### Re: Delta G°

Looking at the equation deltaG°=-RTlnK, if K=1, that means the products and reactants are of the same concentration, and thus lnK=0, and deltaG° will equal 0.

Nathan Tu 2C
Posts: 46
Joined: Fri Sep 29, 2017 7:07 am

### Re: Delta G°

In an equilibrium reaction, delta G is equal to zero when the reaction reaches equilibrium. This is because at equilibrium the free energy of the reactants equals the free energy of the products, making the difference in free energy zero.