## thermodynamically favored

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Michelle Chernyak 1J
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Joined: Fri Sep 29, 2017 7:06 am

### thermodynamically favored

When it says a reaction is thermodynamically favored, it is referring to just the enthalpy or the free energy?

Shannon Wasley 2J
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### Re: thermodynamically favored

just free energy

Tia Tomescu 2D
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Joined: Fri Sep 29, 2017 7:06 am

### Re: thermodynamically favored

Thermodynamically favored means the reaction will proceed spontaneously, and it refers to deltaG, the free energy.

Emma Li 2C
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### Re: thermodynamically favored

I think the reaction can proceed spontaneously even when delta H is positive, so maybe it just refers to free energy?

Julianna Thrasher 1B
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Joined: Thu Jul 27, 2017 3:00 am

### Re: thermodynamically favored

A reaction that is thermodynamically favored has a negative ΔG, so the products are at a lower energy than the reactants so that reaction will spontaneously occur. For ΔG to be negative, ΔH has to be small in the equation ΔG=ΔH−TΔS.

Irma Ramos 2I
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### Re: thermodynamically favored

It refers to the free energy which must be negative in oder to be favored and because of this the entropy is positive and the process is spontaneous.

Nathan Tu 2C
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Joined: Fri Sep 29, 2017 7:07 am

### Re: thermodynamically favored

It refers to the gibbs free energy, which is partly dependent on enthalpy. In a sense, its both, but the specific criteria we use to determine whether a reaction is thermodynamically favored is gibbs free energy.