11.21






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lizzygaines1D
Posts: 52
Joined: Thu Jul 13, 2017 3:00 am

11.21

Postby lizzygaines1D » Tue Feb 06, 2018 9:59 pm

Calculate the standard Gibbs Free energy for I2(g)--->2I(g) when K=6.8 at 1200 K. So using deltaG=deltaGrxn+RTlnQ, I understand how to solve for everything else, but how would you find Q if you are not given a pressure or anything for the products and reactants?

Samantha Kan 2L
Posts: 30
Joined: Sat Jul 22, 2017 3:00 am

Re: 11.21

Postby Samantha Kan 2L » Wed Feb 07, 2018 10:40 am

For this question, you don't need Q because the problem is assuming the reactants and products are at equilibrium. To find the standard Gibbs free energy, you just have to use the equation delta G = -RTlnK. Hope this helps!

Justin Chu 1G
Posts: 52
Joined: Thu Jul 13, 2017 3:00 am
Been upvoted: 1 time

Re: 11.21

Postby Justin Chu 1G » Wed Feb 07, 2018 10:41 am

Yea when the reaction is at equilibrium, you can simply use the K that's given to you.


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