In what circumstance will delta G be zero?
When will delta S be zero?
(Please do not speak in terms of the values of enthalpy and entropy. I want a conceptual explanation, not a numerical one)
Circumstances of delta G
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Re: Circumstances of delta G
When deltaG=0, K is equal to one. This means that the reaction is at equilibrium, and the products/reactants are equally favored.
When deltaS=0, we would be talking about a perfect crystal, where there is only one possible state that each particle can be in.
When deltaS=0, we would be talking about a perfect crystal, where there is only one possible state that each particle can be in.
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Re: Circumstances of delta G
ΔG=0 when the system is at equilibrium. For instance, if ice and water in equilibrium then the Gibbs free energy of 1 mol H2O(l) will be the same as the Gibbs free energy of 1 mol H2O(s).
ΔS=0 is also equilibrium. If ΔS=0, it means that neither the forward nor the reverse reaction/process is spontaneous. It is important to remember that this is ΔStotal which is composed of the ΔSsystem and ΔSsurroundings. When S=0, we have a perfect crystal, not ΔS=0. Hope this helps!
ΔS=0 is also equilibrium. If ΔS=0, it means that neither the forward nor the reverse reaction/process is spontaneous. It is important to remember that this is ΔStotal which is composed of the ΔSsystem and ΔSsurroundings. When S=0, we have a perfect crystal, not ΔS=0. Hope this helps!
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Re: Circumstances of delta G
In addition, Gibbs free energy represents energy that is free to do useful work, so when delta G is zero i guess that means that there is no change in the amount of energy that is free to do work
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