delta G=0
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delta G=0
When delta G=0, does that mean delta H and delta S are both zero too? Or they have numerical values that cancel?
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Re: delta G=0
Either delta H and delta S are 0, indicating that no reaction occurred, or delta H = T delta S and they cancel out.
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Re: delta G=0
Delta G=0 Does not necessarily mean delta H and delta S are zero as well. Delta G=0 means that the process is at equilibrium.
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Re: delta G=0
Delta G=delta H - TdeltaS so if delta G=0 then either both delta H and delta S are zero or delta H equals T times delta S
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Re: delta G=0
It does not necessarily mean that delta H an delta S are zero. When delta G =0, the system is at equilibrium. Therefore, either delta H or delta S is zero or delta S is equal to delta H.
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Re: delta G=0
When delta g is 0, it just means that it is at equilibrium. It is not enough to assume the other two quantities to alse be at 0.
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