9.13 Gibbs free energy of formation






Moderators: Chem_Mod, Chem_Admin

Paula Sing 1J
Posts: 36
Joined: Fri Sep 29, 2017 7:06 am

9.13 Gibbs free energy of formation

Postby Paula Sing 1J » Sat Feb 10, 2018 6:04 pm

In the last paragraph on page 353, it says " A thermodynamically stable compound is a compound with a negative standard Gibbs free energy of formation. A thermodynamically unstable compound is a compound with a positive standard Gibbs free energy of formation." Why is this so if when delta G is negative, a reaction is considered spontaneous and vice versa? Wouldn't a spontaneously decomposing compound be less stable and therefore have a negative delta G value?

Ridhi Ravichandran 1E
Posts: 35
Joined: Sat Jul 22, 2017 3:01 am

Re: 9.13 Gibbs free energy of formation

Postby Ridhi Ravichandran 1E » Sat Feb 10, 2018 9:11 pm

The reaction they are referring to has the compound as the product. For example, the reaction H2 + (1/2)O2 ----> H2O would have a certain Delta G, which would also equal the delta G of formation for H2O. If delta G were negative, the reaction would move in the forward direction and H2O would spontaneously form, not decompose. That is what they mean by H2O being stable. If delta G were positive, the reverse process would be spontaneous, so the decomposition of H2O would be spontaneous. Thus, H2O would spontaneously decompose and would therefore be unstable.


Return to “Gibbs Free Energy Concepts and Calculations”

Who is online

Users browsing this forum: No registered users and 6 guests