## deltaG=0, Phases Coexist ?

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Kyle Sheu 1C
Posts: 87
Joined: Fri Jun 23, 2017 11:39 am

### deltaG=0, Phases Coexist ?

When, for example, Br2(l) --> Br2(g), it is said that at the boiling point, the liquid and gaseous phases are in equilibrium and coexist. How would we visualize the "coexistence" of two different phases?

^I understand this concept in terms of spontaneity but am unsure of what it means in terms of molecular interactions.

Cynthia Tsang
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Joined: Fri Sep 29, 2017 7:07 am
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### Re: deltaG=0, Phases Coexist ?

Some are liquid particles and loosely bound together and others are gaseous and flowing throughout the mixture.

Tiffany 1B
Posts: 32
Joined: Fri Sep 29, 2017 7:05 am

### Re: deltaG=0, Phases Coexist ?

Hi,
Yeah so since at boiling point the particles don't have a higher tendency to go to liquid over gas or vice versa, you could just imagine some particles as gas and others as a liquid at this point. Hope that helps.

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