## 9.81

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Hailey Johnson
Posts: 31
Joined: Wed Nov 16, 2016 3:04 am

### 9.81

In the solutions manual we write the reaction 4Fe3O4 + O2----> 6Fe2O3. Can someone explain why Fe3O4 is on the reactant side and not Fe2O3?

SantanaRodriguezDis1G
Posts: 56
Joined: Sat Jul 22, 2017 3:00 am

### Re: 9.81

I was also wondering how you know to set up the equation in this manner

404995677
Posts: 82
Joined: Fri Sep 29, 2017 7:07 am

### Re: 9.81

It doesnt matter which is on the reactant or product side. If Fe3O4 was on the product side (6FeO3 --> 4 Fe3O4 + O2), the delta G would be +391.6 kJ/mol, thus it would mean the formation of Fe3O4 would not be spontaneous and the reaction would favor the reactants (Fe2O3).

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