## delta H

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Simrina Desar Dis 1H
Posts: 49
Joined: Fri Sep 29, 2017 7:04 am

### delta H

Why are exothermic reactions favored if exothermic involves forming bonds?

Nickolas Manipud 1C
Posts: 60
Joined: Fri Sep 29, 2017 7:07 am

### Re: delta H

Molecules want to achieve a low energy state so they do this by releasing energy through the formation of bonds

Nicole Nikolov 1K
Posts: 50
Joined: Fri Sep 29, 2017 7:05 am

### Re: delta H

Forming a bond releases energy, thus reducing the energy of the molecule. The molecule will therefore be more stable since it is at a lower energy state.

Jessica Patzlaff 1A
Posts: 28
Joined: Fri Sep 29, 2017 7:05 am

### Re: delta H

Energy is released when bonds form and energy is put into a bond in order to break it. As a result, if the energy released by forming the bonds of the products is greater than the energy it took to break the bonds of the reactants than the change in H is negative and it is a exothermic reaction

Ya Gao
Posts: 52
Joined: Fri Sep 29, 2017 7:04 am
Been upvoted: 1 time

### Re: delta H

Both endothermic and exothermic reactions involve forming bonds but exothermic reactions are favored because even though it is forming bonds, the energy of the products is lower than the energy of the reactants.