## Gibbs and Stability

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

K Stefanescu 2I
Posts: 68
Joined: Fri Sep 29, 2017 7:04 am

### Gibbs and Stability

Why are positive G values representative of instability for the given molecule?

RyanS2J
Posts: 32
Joined: Thu Jul 27, 2017 3:00 am

### Re: Gibbs and Stability

Molecules in nature tend to proceed toward their most stable state. A chemical reaction with a positive Gibbs free energy is nonspontaneous, which means energy is required to move the molecule from its current state to a less stable state (for were the reaction spontaneous, no energy input would be needed, as molecules already by nature tend to proceed toward stability).