## ∆Gº temperature

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Lindsay H 2B
Posts: 50
Joined: Fri Sep 29, 2017 7:07 am
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### ∆Gº temperature

Whenever working with the standard Gibbs free energy, does that mean temperature MUST be 298K? because question 11.21 asks for the standard Gibbs free energy and then part (a) says that T=1200 K.

Ethan-Van To Dis2L
Posts: 50
Joined: Fri Sep 29, 2017 7:05 am

### Re: ∆Gº temperature

It just means you're using the standard states of the element at a certain temperature, not specifically 298 K.