### 11.15

Posted:

**Tue Feb 13, 2018 11:15 am**(a) Calculate the reaction Gibbs free energy of I2(g) -> 2 I(g) at 1200. K (K =6.8) when the partial pressures of I2 and I are 0.13 bar and 0.98 bar, respectively. (b) What is the spontaneous direction of the reaction? Explain briefly.

For this question, why does the solutions manual calculate ∆G° using 1200. K instead of 298 K? Since ∆G° is the Gibbs Free Energy of the reaction at standard state, shouldn't we use 298 K?

For this question, why does the solutions manual calculate ∆G° using 1200. K instead of 298 K? Since ∆G° is the Gibbs Free Energy of the reaction at standard state, shouldn't we use 298 K?