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11.15

Posted: Tue Feb 13, 2018 11:15 am
by Ryan Fang 1D
(a) Calculate the reaction Gibbs free energy of I2(g) -> 2 I(g) at 1200. K (K =6.8) when the partial pressures of I2 and I are 0.13 bar and 0.98 bar, respectively. (b) What is the spontaneous direction of the reaction? Explain briefly.

For this question, why does the solutions manual calculate ∆G° using 1200. K instead of 298 K? Since ∆G° is the Gibbs Free Energy of the reaction at standard state, shouldn't we use 298 K?

Re: 11.15

Posted: Tue Feb 13, 2018 11:19 am
by Kelly Kiremidjian 1C
the question states that the reaction is at 1200K

Re: 11.15

Posted: Tue Feb 13, 2018 11:19 am
by Britney Alvey 1B
The question states that the reaction is happening at 1200K so you would use this value to calculate deltaG. The solutions manual calculates delta G not . This is an important distinction because would be calculated at 298K by definition.