deltaG and deltaS(sys) at zero






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Clement Ng
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deltaG and deltaS(sys) at zero

Postby Clement Ng » Tue Feb 13, 2018 12:14 pm

A sample of 1 mole of gas initially at 1 atm and 298 K is heated at constant pressure to 350 K, then the gas is compressed isothermally to its initial volume and is then cooled to 298 K at constant volume.

Why are deltaS(sys) and deltaG zero in this case? Which equations would you use to figure what factors are at zero?

ZoeHahn1J
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Re: deltaG and deltaS(sys) at zero

Postby ZoeHahn1J » Tue Feb 13, 2018 2:48 pm

delta S is zero because change in entropy is a state function, and the final and initial volumes are the same. delta G is zero when a reaction is at equilibrium.


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