## 9.99

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Cam Bear 2F
Posts: 60
Joined: Thu Jul 27, 2017 3:01 am

### 9.99

For this problem "show that, if another molecule such as ethene is present to act as a hydrogen acceptor then the overall process is spontaneous" why do you have to multiply the reaction of ethene with hydrogen by 3?

Suchita 2I
Posts: 59
Joined: Fri Sep 29, 2017 7:04 am

### Re: 9.99

Since the question refers to a hydrogen acceptor I would assume that it means that all the hydrogen produced would be accepted by the ethene. Since 3 moles are produced, the equation for the hydrogenation of ethene is multiplied by 3 to cancel out the hydrogen produced. I would think of this as a Hess' Law-like approach, if that makes sense.