## Endothermic Favorable?

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Amanda Mac 1C
Posts: 58
Joined: Fri Sep 29, 2017 7:05 am

### Endothermic Favorable?

Why are endothermic reactions not favorable at high temperatures?

Curtis Wong 2D
Posts: 62
Joined: Sat Jul 22, 2017 3:00 am

### Re: Endothermic Favorable?

If you have an endothermic reaction, that means Delta H is positive. Delta S depends. If Delta S was positive, then by Delta G = Delta H - T*Delta S, the reaction would be favorable at high temperatures. If Delta S was negative, then the reaction would not be favorable at any temperature.

Veronica Rasmusen 2B
Posts: 49
Joined: Sat Jul 22, 2017 3:01 am

### Re: Endothermic Favorable?

Look at the equation delta G = delta H - T(delta S)
If a reaction is endothermic then delta H will be positive. It depends whether delta S is negative or positive, and whether T is a high or low value to determine whether delta G will be negative (which would mean the reaction is favorable). If Delta S is negative, that means delta G would never be negative as a positive delta H minus a negative T times Delta S would always be positive. If Delta S is positive, than T would have to be high enough to make T times delta S a greater value than delta H, thus making delta G negative as well.