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Standard ∆G for a system at equilibrium

Posted: Wed Feb 14, 2018 11:32 am
by Xihui Yin 1I
It says that standard ∆G for a system at equilibrium=0, but why for varying values of K, representing a system at equilibrium as well, not equal to ∆G=0 itself? I.e. K>1, ∆G<0 as opposed to ∆G=0.

Re: Standard ∆G for a system at equilibrium

Posted: Wed Feb 14, 2018 11:50 am
by Xihui Yin 1I
Nvm, I figured out that ∆G=0 for equilibirum but ∆G° varies for different magnitudes of K.

Re: Standard ∆G for a system at equilibrium

Posted: Thu Feb 15, 2018 5:31 pm
by Ramya Lakkaraju 1B
Make sure to distinguish between delta G and delta G knot since I think that is what is confusing.

Re: Standard ∆G for a system at equilibrium

Posted: Thu Feb 15, 2018 8:46 pm
by Harrison Wang 1H
Standard change in free energy of a system at equilibrium is not 0, but rather related to the equilibrium constant K at that temperature. If K is >1, then standard change in free energy will be -, and if K<1, then standard change in free energy is +. It is delta g or change in energy that is 0 for a system at equilibrium