## enthalpy of sublimation

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Stephanie tran 1J
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Joined: Fri Sep 29, 2017 7:04 am

### enthalpy of sublimation

Do we need to know the enthalpy of sublimation for the final?

Tasnia Haider 1E
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### Re: enthalpy of sublimation

I'm pretty sure you need to know all the enthalpies, but they should be on the equations sheet.

Kyle Alves 3K
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### Re: enthalpy of sublimation

I think the only case it would show up is if we know both the Hvapor and Hsolid, which would make Hsublimation = Hvapor - H solid
and in all cases its endothermic and a positive value!

Fatima_Iqbal_2E
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### Re: enthalpy of sublimation

The numerical value should be given to us, but it is important to know the relationship between $H_{vapor}, H_{solid}, and H_{sublimation}$, as stated above!

Rishi Khettry 1L
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### Re: enthalpy of sublimation

Hsub can also be deltaH(fusion) + deltaH(vaporization)

Pooja Nair 1C
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### Re: enthalpy of sublimation

As long as you know the equation, delta Hsub = Hvapor - Hsolid, or delta Hsub = delta Hfus + delta Hvap, you should be fine. Just remember that sublimation is changing two states, rather than just one phase transition. Since enthalpy is a state function, you can just add the enthalpy of each phase transition to find the enthalpy of sublimation.