## Delta G=0

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Mahir_Hasan2C
Posts: 60
Joined: Fri Sep 28, 2018 12:25 am

### Delta G=0

Why is delta G equal to 0 at constant temperature and pressure?

505211599
Posts: 60
Joined: Fri Sep 28, 2018 12:28 am

### Re: Delta G=0

the delta G is usually 0 if the reaction is in a state of equilibrium.