## Elements with Gibbs Free Energy

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Xuan Kuang 2L
Posts: 31
Joined: Wed Nov 14, 2018 12:23 am

### Elements with Gibbs Free Energy

Do all elements in their most stable form have standard Gibbs Free Energy of formation of zero? If so, could someone conceptually explain to me why this is so?

Srikar_Ramshetty 1K
Posts: 64
Joined: Fri Sep 28, 2018 12:27 am

### Re: Elements with Gibbs Free Energy

Elements in their standard state have an enthalpy of formation(deltaH) equal to 0. This does not mean Gibbs.

deltaH(formation) = 0

Then,
deltaG = deltaH -TdeltaS
deltaG = 0 - TdeltaS

Delta G is equal to 0 when the reaction is at equilibrium, which also means when K=1.
Hope this helps.