## Sign of Free Energy

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Lumbini Chandrasekera 1B
Posts: 63
Joined: Fri Sep 28, 2018 12:18 am

### Sign of Free Energy

How do you determine the sign of Gibbs Free Energy given that enthalpy is positive, temperature is positive, and entropy is positive.

Noah Cook 3O
Posts: 31
Joined: Fri Sep 28, 2018 12:20 am

### Re: Sign of Free Energy

That would depend on the values of those variables. If the value of temperature multiplied by entropy is greater than the value of enthalpy, then your sign for Gibbs Free Energy will be negative and vice versa for a positive value.

Michael Torres 4I
Posts: 92
Joined: Thu May 10, 2018 3:00 am
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### Re: Sign of Free Energy

If such problem were to arise, you would need to be given specific values for enthalpy, temperature, and entropy in order to find the sign of Gibbs Free Energy. Either that, or you would need to be given some means to find those values. Without that information you would be unable to determine the sign based on the formula alone.

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