## Delta G vs. Delta G (degree sign)

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

rkang00
Posts: 69
Joined: Fri Sep 28, 2018 12:25 am

### Delta G vs. Delta G (degree sign)

How is the delta G and the standard state delta G (with degree sign) differ? Is the standard state delta G constant for a specific rxn while delta G (w/o the degree) could be different?

Chloe Qiao 4C
Posts: 65
Joined: Fri Sep 28, 2018 12:27 am

### Re: Delta G vs. Delta G (degree sign)

I think you are right. Delta G depends on specific conditions the reaction is in, but standard delta G is just under standard conditions, which means that standatd delta G will be constant for a reaction.

Karan Thaker 2L
Posts: 75
Joined: Fri Sep 28, 2018 12:26 am

### Re: Delta G vs. Delta G (degree sign)

Remember that standard conditions are 1 atm and 298 K, meaning it's constant.

Kessandra Ng 1K
Posts: 67
Joined: Fri Sep 28, 2018 12:25 am

### Re: Delta G vs. Delta G (degree sign)

Just to add on, if there's a º to something, i.e. ∆Gº or ∆Hº or ∆Sº, it always refers to "under standard conditions" so you would already know T = 298 K and P = 1 atm.

Cole Elsner 2J
Posts: 88
Joined: Fri Sep 28, 2018 12:25 am

### Re: Delta G vs. Delta G (degree sign)

It's just the difference between standard conditions and specific conditions for a system.