Delta G

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

aaronharouni
Posts: 72
Joined: Fri Sep 28, 2018 12:15 am

Delta G

Is delta g considered a state function?

Joanna Pham - 2D
Posts: 113
Joined: Fri Apr 06, 2018 11:04 am

Re: Delta G

I know for sure that Gibbs free energy itself is a state function. I’m not too sure about the change in G though.

AlyssaBei_1F
Posts: 99
Joined: Fri Sep 28, 2018 12:17 am

Re: Delta G

The çhange in G is not dependent on path taken so it would not be a state function.

Aria Soeprono 2F
Posts: 64
Joined: Fri Sep 28, 2018 12:27 am

Re: Delta G

If it's not dependent on the path taken, then it is a state function.

Jacob Bershatski 4C
Posts: 30
Joined: Fri Sep 28, 2018 12:21 am

Re: Delta G

Gibbs free energy itself is a state function. Because it is a state function, we only ever need to consider the change in G from its initial state to its final state because state functions are independent of the path taken by the system.

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