## Equilibrium

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Jessica Tsui 1H
Posts: 30
Joined: Fri Sep 28, 2018 12:21 am

### Equilibrium

Why is a reaction at equilibrium have $\Delta$G = 0?

Laura Gong 3H
Posts: 89
Joined: Fri Sep 28, 2018 12:26 am
Been upvoted: 1 time

### Re: Equilibrium

If the system is at equilibrium, its free energy is not changing. Therefore, Delta G = 0.

Kevin ODonnell 2B
Posts: 62
Joined: Fri Sep 28, 2018 12:24 am

### Re: Equilibrium

This graph helps demonstrate the point if you are more visual or mathematical. Where you can see the forward and reverse reaction meet at a minimum. This minimum is equilibrium in this reaction and shows why since it is a minimum equilibrium would be 0.
Attachments
dGdGo_1.png (33.95 KiB) Viewed 131 times

Elizabeth Kim 4E
Posts: 60
Joined: Fri Sep 28, 2018 12:29 am

### Re: Equilibrium

At equilibrium, free energy equals 0, which means g=0